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2021-10-13
You’ve rearranged an expression to get $$(8 - 2a^2)x^2 + (24 - 4ab)xy + (18-2b^2)y^2 = 0$$ What must now be true for it to always equal zero for positive integers $x$ and $y$??
$$ 2a^2 = 8 $$ $$ 4ab = 24 $$ $$ 2b^2 = 18 $$
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date: 2021-10-13 07:09
summary: what sequence always produces numbers whose difference of successive squares is interesting?
tags:
- '@?public'
- '@?mat'
- '@?notes'
- '@?maths'
title: MAT - Paper 2008 - Q2