Flashcards
2021-10-23
$$4c^3 - 6c^2 + 1 = 0$$ You know that $c$ has to be between $0$ and $1$. What should be the first step in tackling this??
Trying to substitute in obvious/convenient values like $\frac{1}{2}$.
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date: 2021-10-23 19:42
summary: how does the area between y = x and y = x^(1/2) change?
tags:
- '@?public'
- '@?mat'
- '@?notes'
- '@?maths'
title: MAT - Paper 2017 - Q3