What is the formula for the sum of the squares of the $n$ natural numbers??
$$ \sum^{n}_{r=1} r^2 = \frac{1}{6}n(n+1)(2n+1) $$
How could you rewrite $\sum^{n}_{r=1} r^2$??
$$ \frac{1}{6}n(n+1)(2n+1) $$
What’s another way of expressing $\frac{1}{6}n(n+1)(2n+1)$??
$$ \sum^{n}_{r=1} r^2 $$
How could you rewrite $\sum^{n}_{r=1} 3r^2$??
$$ \frac{1}{3}n(n+1)(2n+1) $$
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date: 2020-09-16 17:57
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title: Further Maths - Sums of Squares